document.write( "Question 30059: A man and his brother have a combined age of 92 years. 26 years ago, the man was 9 times as old as his brother. How old is the man? How old is the brother \n" ); document.write( "

Algebra.Com's Answer #16799 by Paul(988) $\"\"$ $\"About$

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Let the man's age be x
\n" ); document.write( "Let his brother's age be y
\n" ); document.write( "x+y=92
\n" ); document.write( "y=92-x (subsitution)\r
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\n" ); document.write( "\n" ); document.write( "26 years ago man's age = x-26
\n" ); document.write( "26 years ago his bro's age = y-26\r
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9(y-26)=x-26
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document.write( "9y-234=x-26
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document.write( "Subsitute:
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document.write( "9(92-x)-234=x-26
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document.write( "828-9x-234=x-26
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document.write( "-9x+594=x-26
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document.write( "-10x=-620
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document.write( "x=62\r
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document.write( "Hence, the man's age is 62 and his brother's age is 30.
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document.write( "Paul.
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