document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29944>Question 29944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand this problem. Could you please help!<BR>\n" );
document.write( "Find the equation of each line and express in the form ax+by=c<BR>\n" );
document.write( "Problem:<BR>\n" );
document.write( "Line passes through (-5, -1) and is perpendicular to -1/3X-Y=2\r<BR>\n" );
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document.write( "Thanks SO MUCH!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16797 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> line (-1/3)x-y=2 --> y = (-1/3)x-2, so its gradient is (-1/3). Any line perpendicular to this has gradient of 3 (2 perpendicular gradients, m*n = -1)\r<BR>\n" );
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document.write( "So we have x=-5, y=-1, m=3...find c from y=mx+c and that will give you the equation of the line.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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