document.write( "Question 224859: An executive drove from home at an average speed of 30mph to an airport where a helicopter was waiting. The executive boarded the helicopter and flew to the corporate offices at an average speed of 60mph. The entire distance was 150 miles. The entire trip took 3 hrs. Find the distance from the airport to the corporate office. \n" ); document.write( "
Algebra.Com's Answer #167968 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An executive drove from home at an average speed of 30mph to an airport where a helicopter was waiting. \n" ); document.write( " The executive boarded the helicopter and flew to the corporate offices at an average speed of 60mph. \n" ); document.write( " The entire distance was 150 miles. \n" ); document.write( " The entire trip took 3 hrs. Find the distance from the airport to the corporate office. \n" ); document.write( ": \n" ); document.write( "Let d = distance from the airport to the office (at 60 mph) \n" ); document.write( "the entire distance give as 150 mi, therefore: \n" ); document.write( "(150-d) = distance from home to airport (at 30 mph) \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "drive time + helicopter time = 3 hrs \n" ); document.write( " \n" ); document.write( "Multiply equation by 60: \n" ); document.write( "60* \n" ); document.write( "Cancel out denominators \n" ); document.write( "2(150-d) + d = 180 \n" ); document.write( "300 - 2d + d = 180 \n" ); document.write( ": \n" ); document.write( "-2d + d = 180 - 300 \n" ); document.write( ": \n" ); document.write( "-d = -120 \n" ); document.write( "d = 120 mi airport to office \n" ); document.write( "then \n" ); document.write( "150 - 120 = 30 min home to airport \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equaiton \n" ); document.write( "30/30 + 120/60 = 3 \n" ); document.write( " |