document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224856>Question 224856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the negative sign is outside of the absolute value what do I do to solve the problem. -|x|>8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167956 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Treat the - sign just like you would a + sign until you divide..<BR>\n" );
document.write( "-|x|>8<BR>\n" );
document.write( "-x>8 <BR>\n" );
document.write( "x<-8 ans. [Note: whwn dividing by a negative value the > sign changes to a < sign.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Also <BR>\n" );
document.write( "-x>-8<BR>\n" );
document.write( "x<-8/-1<BR>\n" );
document.write( "x<8 ans. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );