document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224800>Question 224800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem.. \"A boat goes downstream a distance of 5 m in 5 min, but it takes 20 min for the return trip. find the rate of the boat in still water and rate of the current\" it will be ok even if it is just the equations... PLEASE PLEASE </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167884 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "5=R*1/12<BR>\n" );
document.write( "5=R/12<BR>\n" );
document.write( "R=5*12<BR>\n" );
document.write( "R=60 MPH SPEED GOING DOWNSTREAM WITH THE SURRENT.<BR>\n" );
document.write( "5=R*1/3<BR>\n" );
document.write( "5=R/3<BR>\n" );
document.write( "R=5*3<BR>\n" );
document.write( "R=15 MPH SPEED GOING UPSTREAM AGAINST THE CURRENT.<BR>\n" );
document.write( "(60-15)/2=45/2=22.5 MPH IS THE SPEED OF THE BOAT IN STILL WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "60-22.5=37.5 MPH IS THE SPEED OF THE CURRENT.<BR>\n" );
document.write( "15+22.5=37.5 DITTO.<BR>\n" );
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