document.write( "Question 220428: please help me solve this problem:
\n" ); document.write( "The perimeter of a triangle is 51 inches. side A is one inche greater than side C. Side B is twice as long as side A. Find the longest side.
\n" ); document.write( "

Algebra.Com's Answer #167878 by LtAurora(115)\"\" \"About 
You can put this solution on YOUR website!
First, lets write all the lengths in terms of side A, since the relations all go back to it.
\n" ); document.write( "So, Side C:
\n" ); document.write( "\"A=C%2B1\"
\n" ); document.write( "\"A-1=C\"
\n" ); document.write( "Side B:
\n" ); document.write( "\"2A=B\"
\n" ); document.write( "Side A:
\n" ); document.write( "\"A=A\"
\n" ); document.write( "So, we knew that \"A%2BB%2BC=51\". However, know we have what C and B are, so we can rewrite:
\n" ); document.write( "\"A%2B2A%2BA-1=51\"
\n" ); document.write( "Move the 1 to the other side and combine the \"A\" terms:
\n" ); document.write( "\"4A=52\"
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "\"A=13\".
\n" ); document.write( "Substituting back in for C & B give us:
\n" ); document.write( "\"B=26\", \"C=12\".
\n" ); document.write( "The longest side is then \"B=26\".
\n" ); document.write( "
\n" );