document.write( "Question 224555: Write the slope intercept form of the equation of the line described.\r
\n" ); document.write( "\n" ); document.write( "through:(4,-4), parallel to y=-x-4
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Algebra.Com's Answer #167869 by drj(1380)\"\" \"About 
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Write the slope intercept form of the equation of the line described.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. We can find the slope by recognizing that parallel lines have the same slope. Since \"y=-x-4\" is in slope-intercept form given as y=mx+b where the slope m=-1 and the y-intercept b=-4 when x=0 or at point (0,b) or (0,-4).\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Now we have to find the line with slope m=-1 going through point (4,-4).\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Given two points (x1,y1) and (x2,y2), then the slope m is given as\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Let (x1,y1)=(4,-4) or x1=4 and y1=-4. Let other point be (x2,y2)=(x,y) or x2=x and y2=y.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Now we're given \"m=1%2F3\". Substituting above values and variables in the slope equation m yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1=%28y-%28-4%29%29%2F%28x-4%29=%28y%2B4%29%2F%28x-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Multiply x-4 to both sides to get rid of denominator on right side of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28x-4%29=y%2B4\" \r
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\n" ); document.write( "\n" ); document.write( "\"-x%2B4=y%2B4\" \r
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\n" ); document.write( "\n" ); document.write( "Step 7 Subtract 4 from both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"-x%2B4-4=y%2B4-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"-x=y\" \r
\n" ); document.write( "\n" ); document.write( "Step 8. ANSWER: The equation in slope-intercept form is \"y=-x\"\r
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\n" ); document.write( "\n" ); document.write( "Note: the above equation can be rewritten as \r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=0\"\r
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\n" ); document.write( "\n" ); document.write( "And the graph is shown below which is consistent with the above steps.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+1+y+=+0\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/1 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/1 = 0.
  • Slope is -1/1 = -1.
  • Equation in slope-intercept form: y=-1*x+0.
\"graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+-1%2Ax%2B0+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps and explanation were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV
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