document.write( "Question 224730: what is the initial velocity of a geyser's boiling water this is the equation h=-16t+70t\r
\n" ); document.write( "\n" ); document.write( "what is the maximum height of the boiling water?
\n" ); document.write( "how long was the boiling water in the air?
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Algebra.Com's Answer #167847 by Alan3354(69443)\"\" \"About 
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what is the initial velocity of a geyser's boiling water this is the equation
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\n" ); document.write( "h=-16t+70t
\n" ); document.write( "I think it's h(t) = -16t^2 + 70t
\n" ); document.write( "h'(t) = -32t + 70
\n" ); document.write( "h'(0) = 70
\n" ); document.write( "The initial velocity = 70 ft/sec
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\n" ); document.write( "what is the maximum height of the boiling water?
\n" ); document.write( "The time of max height is half of the flight time. From below, total time = 4.375 seconds.
\n" ); document.write( "1/2 is 2.1875 seconds the time at apogee
\n" ); document.write( "h(2.1875) = -16*2.1875^2 + 70*2.1875
\n" ); document.write( "max h = 76.5625 feet
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\n" ); document.write( "how long was the boiling water in the air?
\n" ); document.write( "Find when it's at h = 0. There will be 2 times, when it left and when it returns.
\n" ); document.write( "-16t^2 + 70t = 0
\n" ); document.write( "t = 0 (eruption)
\n" ); document.write( "t = 70/16 seconds
\n" ); document.write( "t = 4.375 seconds
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\n" ); document.write( "It's assumed that there's no evaporation and no air resistance.
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