document.write( "Question 224721: Use patterns or a linear equation to complete the table.\r
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Algebra.Com's Answer #167839 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Use patterns or a linear equation to complete the table.\r
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\n" ); document.write( "\n" ); document.write( "Based on the Steps below the equation is \"y=2x-3\"\r
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\n" ); document.write( "\n" ); document.write( "1 y=2(1)-3=-1\r
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\n" ); document.write( "\n" ); document.write( "-1 y=2(-1)-3=-5\r
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\n" ); document.write( "\n" ); document.write( "3 3 use this point to find slope and equation of line (see below)\r
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\n" ); document.write( "\n" ); document.write( "5 7 use this point to find slope and equation of line (see below)\r
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\n" ); document.write( "\n" ); document.write( "10 ? y=2(10)-3=17\r
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\n" ); document.write( "\n" ); document.write( "50 ? y=2(50)-3=100-3=97\r
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\n" ); document.write( "\n" ); document.write( "Step 1. We are going to find the equation for this line in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point(0,b). Once we have this equation we can get the rest of the points.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Based on your problem we will use two points to draw a line and these points are (3,3) and (5,7)\r
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\n" ); document.write( "\n" ); document.write( "Step 3. The slope of the line m is given as\r
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\n" ); document.write( "\n" ); document.write( "\"+m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "where for our example is x1=3, y1=3, x2=5 and y2=7 (think of \"slope=rise%2Frun\"). You can choose the points the other way around but be consistent with the x and y coordinates. You will get the same result.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Substituting the above values in the slope equation gives\r
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\n" ); document.write( "\n" ); document.write( "\"m=%287-3%29%2F%285-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=4%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5. The slope is calculated as 2 or m=-2\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Now use the slope equation of step 1 and choose one of the given points. I'll choose point (3,3). Letting y=y2 and x=x2 and substituting m=2 in the slope equation given as,\r
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\n" ); document.write( "\n" ); document.write( "\"+m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+2=%28y-3%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+2=%28y-3%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 7. Multiply both sides of equation by x-3 to get rid of denomination found on the right side of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"+2%28x-3%29=%28x-3%29%28y-3%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+2%28x-3%29=y-3\"\r
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\n" ); document.write( "\n" ); document.write( "Step 8. Now simplify and put the above equation into slope-intercept form.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-6=y-3\"\r
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\n" ); document.write( "\n" ); document.write( "Add 3 to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"2x-6%2B3=y-3%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3=y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=2x-3\" is in in slope-intercept form where m=2 and y-intercept=-3\r
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\n" ); document.write( "\n" ); document.write( "Step 9. See if the other point (5,7) or x=5 and y=7 satisfies this equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=2%2Ax-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"7=2%2A5-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"7=7\" So the point (5,7) satisfies the equation and is on the line. In other words, you can use the other point to check your work.\r
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\n" ); document.write( "\n" ); document.write( "Note the above equation can be also be transform into standard form as\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2By=-3\"\r
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\n" ); document.write( "\n" ); document.write( "See graph below to check the above steps.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"-2+x+%2B+1+y+=+-3\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+--2%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -3/-2 = 1.5.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -3/1 = -3.
  • Slope is --2/1 = 2.
  • Equation in slope-intercept form: y=2*x+-3.
\"graph%28+500%2C+500%2C+1.5-8%2C+1.5%2B8%2C+-3-8%2C+-3%2B8%2C+2%2Ax%2B-3+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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