document.write( "Question 224686: A chemist wants to mix a 60% saline solution with 20 liters of a 45% saline solution to obtain a 55% saline solution. How much of the 60% solution should she use?
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Algebra.Com's Answer #167829 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .80*20+.45x=.55(20+x) \n" ); document.write( "16+.45x=11+.55x \n" ); document.write( ".45x-.55x=11-16 \n" ); document.write( "-.10x=-5 \n" ); document.write( "x=-5/-.1 \n" ); document.write( "x=50 liters of 60% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".80*20+.45*50=.55(20+50) \n" ); document.write( "16+22.5=.55*70 \n" ); document.write( "38.5=38.5 \n" ); document.write( " \n" ); document.write( " |