document.write( "Question 224466: kim is 1/3 the age of her older sister sue. in 13 years, sue will be one year younger than twice kim's age. how old is sue?\r
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document.write( "Please help me. Thanks! \n" );
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Algebra.Com's Answer #167792 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let k = Kim's present age \n" ); document.write( "Let s = Sue's present age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"kim is 1/3 the age of her older sister sue.\" \n" ); document.write( "k = \n" ); document.write( "or \n" ); document.write( "s = 3k; may use it this way for substitution \n" ); document.write( "; \n" ); document.write( "\" in 13 years, sue will be one year younger than twice kim's age.\" \n" ); document.write( "s + 13 = 2(k + 13) - 1 \n" ); document.write( "Simplify the equation as much as possible \n" ); document.write( "s + 13 = 2k + 26 - 1 \n" ); document.write( "s + 13 = 2k + 25 \n" ); document.write( "s = 2k + 25 - 13 \n" ); document.write( "s = 2k + 12 \n" ); document.write( ": \n" ); document.write( " how old is sue? \n" ); document.write( ": \n" ); document.write( "Substitute 3k for s in the above equation, find k \n" ); document.write( "3k = 2k + 12 \n" ); document.write( "3k - 2k = 12 \n" ); document.write( "k = 12 yrs is Kim's present age \n" ); document.write( "then \n" ); document.write( "s = 3k \n" ); document.write( "s = 3(12) \n" ); document.write( "s = 36 is Sue's present age \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check our solution in the statement: \n" ); document.write( "\"in 13 years, sue will be one year younger than twice kim's age. \n" ); document.write( "36 + 13 = 2(12 + 13) - 1 \n" ); document.write( "49 = 2(25) - 1; confirms our solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this make sense to you? \n" ); document.write( " |