document.write( "Question 224466: kim is 1/3 the age of her older sister sue. in 13 years, sue will be one year younger than twice kim's age. how old is sue?\r
\n" ); document.write( "\n" ); document.write( "Please help me. Thanks!
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Algebra.Com's Answer #167792 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let k = Kim's present age
\n" ); document.write( "Let s = Sue's present age
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"kim is 1/3 the age of her older sister sue.\"
\n" ); document.write( "k = \"1%2F3\"s
\n" ); document.write( "or
\n" ); document.write( "s = 3k; may use it this way for substitution
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\n" ); document.write( "\" in 13 years, sue will be one year younger than twice kim's age.\"
\n" ); document.write( "s + 13 = 2(k + 13) - 1
\n" ); document.write( "Simplify the equation as much as possible
\n" ); document.write( "s + 13 = 2k + 26 - 1
\n" ); document.write( "s + 13 = 2k + 25
\n" ); document.write( "s = 2k + 25 - 13
\n" ); document.write( "s = 2k + 12
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\n" ); document.write( " how old is sue?
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\n" ); document.write( "Substitute 3k for s in the above equation, find k
\n" ); document.write( "3k = 2k + 12
\n" ); document.write( "3k - 2k = 12
\n" ); document.write( "k = 12 yrs is Kim's present age
\n" ); document.write( "then
\n" ); document.write( "s = 3k
\n" ); document.write( "s = 3(12)
\n" ); document.write( "s = 36 is Sue's present age
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\n" ); document.write( "Check our solution in the statement:
\n" ); document.write( "\"in 13 years, sue will be one year younger than twice kim's age.
\n" ); document.write( "36 + 13 = 2(12 + 13) - 1
\n" ); document.write( "49 = 2(25) - 1; confirms our solution
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\n" ); document.write( "Did this make sense to you?
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