document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224625>Question 224625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the perimeter and the area of a rectangle with length (x+3) and width 7?\r<BR>\n" );
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document.write( "I have tried to do this but the x is confusing me .. like for the perimeter would it be x + 20 .. or 20x?. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167786 by </B><A HREF=/tutors/aboutme.mpl?userid=mestrydilip><B>mestrydilip(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mestrydilip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mestrydilip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = x+3\r<BR>\n" );
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document.write( "Width = 7\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2*Length + 2*Width\r<BR>\n" );
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document.write( "Perimeter = 2(x+3) + 2*7\r<BR>\n" );
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document.write( "Perimeter = 2x+6+14 = 2x+20\r<BR>\n" );
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document.write( "Area = Length * Width = (x+3)*7 = 7x+21\r<BR>\n" );
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