document.write( "Question 224571: the length of a rectangle is three centimeters greater than the width. If the perimeter equals 54 centimeters. \n" ); document.write( "

Algebra.Com's Answer #167753 by drj(1380) $\"\"$ $\"About$

You can put this solution on YOUR website!
The length of a rectangle is three centimeters greater than the width. If the perimeter equals 54 centimeters.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The perimeter P means adding up all the four sides of a rectangle.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let w be the width.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let w+3 be the length\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Then, P=w+w+w+3+w+3=54.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Solving yields the following steps\r
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Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

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\n" ); document.write( " YOUR ANSWER\n" ); document.write( "

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This is an equation! Solutions: w=12.
Graphical form: Equation $\"w%2Bw%2Bw%2B3%2Bw%2B3=54\"$ was fully solved.
Text form: w+w+w+3+w+3=54 simplifies to 0=0
Cartoon (animation) form: $\"simplify_cartoon%28+w%2Bw%2Bw%2B3%2Bw%2B3=54+%29\"$
For tutors: simplify_cartoon( w+w+w+3+w+3=54 )
If you have a website, here's a link to this solution.

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DETAILED EXPLANATION

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Look at $\"w%2Bw%2Bw%2Bhighlight_red%28+3+%29%2Bw%2Bhighlight_red%28+3+%29=54\"$ .
Added fractions or integers together
It becomes $\"w%2Bw%2Bw%2Bhighlight_green%28+6+%29%2Bw=54\"$ .
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Look at $\"w%2Bw%2Bw%2Bhighlight_red%28+6+%29%2Bw=54\"$ .
Moved $\"6\"$ to the right of expression
It becomes $\"w%2Bw%2Bw%2Bw%2Bhighlight_green%28+6+%29=54\"$ .
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Look at

.
Eliminated similar terms $\"highlight_red%28+w+%29\"$ , $\"highlight_red%28+w+%29\"$ , $\"highlight_red%28+w+%29\"$ , $\"highlight_red%28+w+%29\"$ replacing them with $\"highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29\"$
It becomes $\"highlight_green%28+%281%2B1%2B1%2B1%29%2Aw+%29%2B6=54\"$ .
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Look at

.
Added fractions or integers together
It becomes $\"%28highlight_green%28+4+%29%29%2Aw%2B6=54\"$ .
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Look at $\"highlight_red%28+%28highlight_red%28+4+%29%29%2Aw+%29%2B6=54\"$ .
Remove unneeded parentheses around factor $\"highlight_red%28+4+%29\"$
It becomes $\"highlight_green%28+4+%29%2Aw%2B6=54\"$ .
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Look at $\"4%2Aw%2B6=highlight_red%28+54+%29\"$ .
Moved these terms to the left $\"highlight_green%28+-54+%29\"$
It becomes $\"4%2Aw%2B6-highlight_green%28+54+%29=0\"$ .
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Look at $\"4%2Aw%2Bhighlight_red%28+6+%29-highlight_red%28+54+%29=0\"$ .
Added fractions or integers together
It becomes $\"4%2Aw%2Bhighlight_green%28+-48+%29=0\"$ .
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Look at $\"4%2Aw%2Bhighlight_red%28+-48+%29=0\"$ .
Removed extra sign in front of $\"-48\"$
It becomes $\"4%2Aw-highlight_green%28+48+%29=0\"$ .
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Look at $\"highlight_red%28+4%2Aw-48+%29=0\"$ .
Solved linear equation $\"highlight_red%28+4%2Aw-48=0+%29\"$ equivalent to 4*w-48 =0
It becomes $\"highlight_green%28+0+%29=0\"$ .
Result: $\"0=0\"$
\n" ); document.write( "This is an equation! Solutions: w=12.

Universal Simplifier and Solver

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Done!

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\n" ); document.write( "\n" ); document.write( "For w=12 , then w+3=15 and P=2(12+15)=54 which is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: The width is 12 cm and the length is 15 cm.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "drjctu@gmail.com\r
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