document.write( "Question 224519: a man invested $25,000, part of it was invested at 3% and the rest at 4%. the total annual income from two investments is $950.00. how much was invested at each of these rates? \n" ); document.write( "
Algebra.Com's Answer #167734 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .04X+.03(25,000-X)=950 \n" ); document.write( ".04X+750-.03X=950 \n" ); document.write( ".01X=950-750 \n" ); document.write( ".01X=200 \n" ); document.write( "X=200/.01 \n" ); document.write( "X=20,000 AMOUNT INVESTED @ 4% \n" ); document.write( "25,000-20,000=5,000 INVESTED @ 3% \n" ); document.write( "PROOF: \n" ); document.write( ".04*20,000+.03*5,000=950 \n" ); document.write( "800+150=950 \n" ); document.write( "950=950 \n" ); document.write( " |