document.write( "Question 224529: A train travels 120 km in the same time that a plane covers 336 km. If the speed of the the plane is 10 km per hour less than 3 times the speed of the train, find both speeds. \n" ); document.write( "
Algebra.Com's Answer #167728 by Earlsdon(6294)\"\" \"About 
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Start with the distance formula: \"d+=+r%2At\" where d = distance, r = rate/speed, and t = time of travel.
\n" ); document.write( "For the train:
\n" ); document.write( "\"d%5B1%5D+=+r%5B1%5D%2At\" Substitute d = 120km
\n" ); document.write( "\"120+=+r%5B1%5D%2At\" Rewrite this as:\"highlight_green%28t+=+120%2Fr%5B1%5D%29\" and substitute into the equation for \"d%5B2%5D\".
\n" ); document.write( "For the plane:
\n" ); document.write( "\"d%5B2%5D+=+r%5B2%5D%2At\" Notice that t (time) is the same in both cases. Substitute d = 336km and \"r%5B2%5D+=+3r%5B1%5D-10\"
\n" ); document.write( "\"336+=+%283r%5B1%5D-10%29%2At\" Substitute, from above, \"highlight_green%28t+=+120%2Fr%5B1%5D%29\"
\n" ); document.write( "\"336+=+%28%283r%5B1%5D%29-10%29%28highlight_green%28120%2Fr%5B1%5D%29%29\" Multiply both sides by\"r%5B1%5D\"
\n" ); document.write( "\"336%2Ar%5B1%5D+=+%28%283r%5B1%5D%29-10%29%2A120%29\" perform the indicated multiplication on the right side.
\n" ); document.write( "\"%28336%29%2Ar%5B1%5D%29+=+360r%5B1%5D-1200\" Add 1200 to both sides.
\n" ); document.write( "\"1200%2B336r%5B1%5D+=+360r%5B1%5D\" Subtract \"336r%5B1%5D\" from both sides.
\n" ); document.write( "\"1200+=+24r%5B1%5D\" Divide both sides by 24.
\n" ); document.write( "\"50+=+r%5B1%5D\" and \"r%5B2%5D+=+3%2850%29-10\"
\n" ); document.write( "\"r%5B1%5D+=+50\"km/hr. and
\n" ); document.write( "\"r%5B2%5D+=+140\"km/hr.
\n" ); document.write( "The train is going 50km/hr. and the plane is going 140km/hr.
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