document.write( "Question 224521: Here is the problem. Directions are to solve and check.
\n" ); document.write( "3m-(m+1)=6m+1\r
\n" ); document.write( "\n" ); document.write( "My work:
\n" ); document.write( "1st. 3m-1m-1=6m+1
\n" ); document.write( "2nd. 2m-1=6m+1
\n" ); document.write( "3rd. 2m-2m-1=-2m+1
\n" ); document.write( "4th. -1=4m+1\r
\n" ); document.write( "\n" ); document.write( "That is as far as I can get. I dont understand what else to do.
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Algebra.Com's Answer #167714 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
You have all the m terms on the right side, so get all the number terms to the left side by subtracting 1 from each side.\r
\n" ); document.write( "\n" ); document.write( "-1=4m+1
\n" ); document.write( "-1-1=4m+1-1
\n" ); document.write( "-2=4m\r
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\n" ); document.write( "\n" ); document.write( "Divide by 4:
\n" ); document.write( "-2/4=4m/4
\n" ); document.write( "-1/2=m\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2
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