document.write( "Question 224515: given f(x)=sqrt x+3 and g(x)=6x find f(g(x)) i.e.(fog)(x) and find (fog)(1)\r
\n" ); document.write( "\n" ); document.write( "I know that you need to replace the x in sqrt of x +3 so it would read sqrt 6x+3\r
\n" ); document.write( "\n" ); document.write( "then would I change that to (6x+3)^2 =36x^2+36x+9. \n" ); document.write( "

Algebra.Com's Answer #167713 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
Your first part is correct. f(g(x)) means to substitute g(x) = 6x into the formula for f, so $\"f%28g%28x%29%29=sqrt%286x%2B3%29+\"$ . However, what you did next was NOT correct. You have a SQUARE ROOT, NOT a SQUARE! Do NOT square it!!!\r
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\n" ); document.write( "\n" ); document.write( "f(g(1)) means to substitute 1 in place of the x. \r
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\n" ); document.write( "\n" ); document.write( "This would be $\"f%28g%281%29%29=+sqrt%286%2B3%29=sqrt%289%29=3\"$ \r
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\n" ); document.write( "\n" ); document.write( "f(g(1)) = 3\r
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\n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( "

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