document.write( "Question 224501: A cable company charges $75 for installation plus $20 per month. Another cable company offers free installation but charges $35 per month. For how many months of cable service would the total cost from either company be the same? \r
\n" ); document.write( "\n" ); document.write( "a)2 b) 3 c) 5 d) 7
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Algebra.Com's Answer #167705 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A cable company charges $75 for installation plus $20 per month. Another cable company offers free installation but charges $35 per month. For how many months of cable service would the total cost from either company be the same?
\n" ); document.write( "a)2 b) 3 c) 5 d) 7
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\n" ); document.write( "1st Co Eq: A(x) = 75 + 20x where x is # of months of service
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\n" ); document.write( "2nd Co Eq; B(x) = 35x where x is # of months of service
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\n" ); document.write( "Equation:
\n" ); document.write( "When does A(x) = B(x)
\n" ); document.write( "75+20x = 35x
\n" ); document.write( "15x = 75
\n" ); document.write( "x = 5 months
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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