document.write( "Question 224339: Me and my friend are trying to do this problem but have no clue how to do it.\r
\n" ); document.write( "\n" ); document.write( "Here's the problem:\r
\n" ); document.write( "\n" ); document.write( "Use the Intermediate Value Theorem to show that there is a root of the equation \"+2x%5E3+%2B+x%5E2+%2B+2+=+0+\" in the interval [-2,-1]\r
\n" ); document.write( "\n" ); document.write( "We have a very vague understanding of what that theorem means but we only worked with letters never an actual equation. Could you please help us? Thanks in advance. =)
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Algebra.Com's Answer #167700 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Use the Intermediate Value Theorem to show that there is a root of the equation \"+2x%5E3+%2B+x%5E2+%2B+2+=+0+\" in the interval [-2,-1]
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\n" ); document.write( "f(x) = 2x^3 + x^2 + 2
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\n" ); document.write( "Calculate f(-2):
\n" ); document.write( "\"+2x%5E3+%2B+x%5E2+%2B+2\"
\n" ); document.write( "\"+2%28-2%29%5E3+%2B+2%5E2+%2B+2\"
\n" ); document.write( "\"+2%28-8%29+%2B+4+%2B+2\"
\n" ); document.write( "\"+-16+%2B+4+%2B+2\"
\n" ); document.write( "\"+-10+\"
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\n" ); document.write( "Calculate f(-1):
\n" ); document.write( "\"+2x%5E3+%2B+x%5E2+%2B+2\"
\n" ); document.write( "\"+2%28-1%29%5E3+%2B+%28-1%29%5E2+%2B+2\"
\n" ); document.write( "\"+2%28-1%29+%2B+1+%2B+2\"
\n" ); document.write( "\"+-2+%2B+1+%2B+2\"
\n" ); document.write( "\"+1\"
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\n" ); document.write( "\"Mean value theorem\" says that if a number (say 0) is between f(-2)=-10 and f(-1)=1 then there will be a value of x that will give you that result.
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\n" ); document.write( "Since 0 lies between -10 and 1 there is a value of x.
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\n" ); document.write( "To find that value, it is best to use a graphing calculator..
\n" ); document.write( "x = -1.197
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\n" ); document.write( "Read up more on \"intermediate value theorem\" at:
\n" ); document.write( "http://en.wikipedia.org/wiki/Intermediate_value_theorem
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