document.write( "Question 224436: If \"5%2Fx=%285%2Ba%29%2F%28x%2Ba%29\" what is the value of x? \n" ); document.write( "
Algebra.Com's Answer #167697 by LtAurora(115)\"\" \"About 
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We can solve this by cross-multiplying to give:
\n" ); document.write( "\"5%28x%2Ba%29=x%285%2Ba%29\"
\n" ); document.write( "Then distribute:
\n" ); document.write( "\"5x%2B5a=5x%2Bxa\"
\n" ); document.write( "Move all the \"x\" terms to one side:
\n" ); document.write( "\"5a=5x-5x%2Bxa\"
\n" ); document.write( "The \"5x\" terms cancel to give:
\n" ); document.write( "\"5a=xa\".
\n" ); document.write( "To get \"x\" by istelf, divide both sides by \"a\".
\n" ); document.write( "\"5a%2Fa=xa%2Fa\"
\n" ); document.write( "Here we see that the \"a\" terms cancel out to yield:
\n" ); document.write( "\"5=x\".
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