document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224357>Question 224357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line through (4,3) perpendicular to the line 3x + y = 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167681 by </B><A HREF=/tutors/aboutme.mpl?userid=chibisan><B>chibisan(131)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chibisan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chibisan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + y = 7<BR>\n" );
document.write( "y = 7-3x\r<BR>\n" );
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document.write( "grad = negative reciprocal of -3 = 1/3\r<BR>\n" );
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document.write( "new equation :<BR>\n" );
document.write( "y = 1/3x + b\r<BR>\n" );
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document.write( "sub(4,3)<BR>\n" );
document.write( "3 = 1/3(4) + b<BR>\n" );
document.write( "3 - 4/3 = b<BR>\n" );
document.write( "5/3 = b\r<BR>\n" );
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document.write( "new equation will be :<BR>\n" );
document.write( "y = 1/3x + 5/3<BR>\n" );
document.write( "3y = x + 5(ans) </SPAN>\n" );
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