document.write( "Question 224362: Solve by using either the addition method or the substitution method
\n" ); document.write( "1/40x-1/5y=-1/8
\n" ); document.write( "x+1/15y=46/15
\n" ); document.write( "The solution is ( , ) \n" ); document.write( "
Algebra.Com's Answer #167680 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
X/40-Y/5=-1/8 MULTIPLY BY 1/3 & ADD.
\n" ); document.write( "X+Y/15=46/15
\n" ); document.write( "X/120-Y/15=-1/24
\n" ); document.write( "----------------------
\n" ); document.write( "X+X/120=46/15-1/24
\n" ); document.write( "(120X+X)/120=(46*24-1*15)/360 MULTIPLY BOTH SIDES BY 120
\n" ); document.write( "121X=(1,104-15)/3
\n" ); document.write( "3*121X=1,089
\n" ); document.write( "363X=1,089
\n" ); document.write( "X=1,089/363
\n" ); document.write( "X=3 ANS.
\n" ); document.write( "3+Y/15=46/15
\n" ); document.write( "Y/15=46/15-3
\n" ); document.write( "Y/15=(46-3*15)/15
\n" ); document.write( "Y/15=(46-45)/15
\n" ); document.write( "Y/15=1/15
\n" ); document.write( "Y=1 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "3/40-1/5=-1/8
\n" ); document.write( "3/40-8/40=-1/8
\n" ); document.write( "-5/40=-1/8
\n" ); document.write( "-1/8=-1/8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The solution is ( , ) \n" ); document.write( "
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