document.write( "Question 224349: A bus traveling at a rate of 60 mph overtakes a car traveling at a rate of 45 mph. If the car had a 1-hour head start, how far from the starting point does the bus overtake the car? \n" ); document.write( "
Algebra.Com's Answer #167675 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A bus traveling at a rate of 60 mph overtakes a car traveling at a rate of 45 mph.
\n" ); document.write( " If the car had a 1-hour head start, how far from the starting point does the bus overtake the car?
\n" ); document.write( ":
\n" ); document.write( "Find the time required by the car to catch up to the bus, then find the distance.
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of the car
\n" ); document.write( "then
\n" ); document.write( "(t+1) = travel time of the bus (on the road 1 hr longer)
\n" ); document.write( ":
\n" ); document.write( "When the car catches up with the bus, they will have traveled the same distance.
\n" ); document.write( "write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Car dist = bus dist
\n" ); document.write( "60t = 45(t+1)
\n" ); document.write( "60t = 45t + 45
\n" ); document.write( "60t - 45t = 45
\n" ); document.write( "15t = 45
\n" ); document.write( "t = \"45%2F15\"
\n" ); document.write( "t = 3 hrs, travel time of the car
\n" ); document.write( ":
\n" ); document.write( "Find the dist
\n" ); document.write( "60 * 3 = 180 mi from the starting point
\n" ); document.write( ":
\n" ); document.write( "Check solution using the bus which traveled 1 hr longer
\n" ); document.write( "45 * 4 = 180 mi, confirms our solution \n" ); document.write( "
\n" );