document.write( "Question 224365: A chemistry student wants to mix an 13% acid solution with a 51% acid solution to g 13L of a 29% acid solution. How many liters of the 13% solution and how many liters of the 51% solution should be mixed\r
\n" ); document.write( "\n" ); document.write( "The mixture contains 7.52632 L of 13% acid solution and 5.47363 L of 51%acid solution
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Algebra.Com's Answer #167674 by checkley77(12844)\"\" \"About 
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.51X+.13(13-X)=.29*13
\n" ); document.write( ".51X+1.69-.13X=3.77
\n" ); document.write( ".38X=3.77-1.69
\n" ); document.write( ".38X=2.08
\n" ); document.write( "X=2.08/.38
\n" ); document.write( "X=5.47368 LITERS OF 51% ACID IS USED.
\n" ); document.write( "13-5.47368=7.52632 LITERS OF 13% ACID IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".51*5.47368+.13*7.52632=3.77
\n" ); document.write( "2.79158+.97842=3.77
\n" ); document.write( "3.77=3.77
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