document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224426>Question 224426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 15x-3=3x-15  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167643 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15x -3 = 3x-15\r<BR>\n" );
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document.write( "Subtract 3x from each side to get all the variables on the left side:<BR>\n" );
document.write( "12x-3=-15\r<BR>\n" );
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document.write( "Add +3 to each side to get all the number terms on the right side:<BR>\n" );
document.write( "12x-3+3=-15+3<BR>\n" );
document.write( "12x=-12<BR>\n" );
document.write( "x=-1\r<BR>\n" );
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document.write( "R^2\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje </SPAN>\n" );
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