document.write( "Question 224277: x+y+z=-2
\n" ); document.write( "-3x-5y-z=6
\n" ); document.write( "2y-3z=2\r
\n" ); document.write( "\n" ); document.write( "How do you solve this?
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Algebra.Com's Answer #167572 by Alan3354(69443)\"\" \"About 
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x+y+z=-2
\n" ); document.write( "-3x-5y-z=6
\n" ); document.write( "2y-3z=2
\n" ); document.write( "How do you solve this?
\n" ); document.write( "-----------
\n" ); document.write( "There are several ways to do it, but since the 3rd equation has no x, I'd use elimination and substitution.
\n" ); document.write( "x+y+z=-2 times 3 --> 3x+3y+3z = -6
\n" ); document.write( "-3x-5y-z=6
\n" ); document.write( "3x+3y+3z=-6
\n" ); document.write( "------------- Add
\n" ); document.write( "-2y + 2z = 0
\n" ); document.write( "+2y - 3z = 2 3rd eqn
\n" ); document.write( "------------ Add
\n" ); document.write( "-z = 2
\n" ); document.write( "z = -2
\n" ); document.write( "-------
\n" ); document.write( "y = -2
\n" ); document.write( "-------
\n" ); document.write( "x = 2\r
\n" ); document.write( "\n" ); document.write( "
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