document.write( "Question 224302: The base of an isosceles triangle is 21 centimeters long. The altitude to the base is 9 centimeters long. What is the approximate measure of a base angle of the triangle \n" ); document.write( "
Algebra.Com's Answer #167563 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! A rough sketch helps to visualize. \n" ); document.write( ". \n" ); document.write( "the base of the isosceles triangle is 21, and the median from the opposite vertex is the height,,, which is 9 \n" ); document.write( ". \n" ); document.write( "This causes a right triangle, legs 9 and 10.5 (21/2) \n" ); document.write( ". \n" ); document.write( "The base angle of the triangle has, tan x = opp/adj = h/(b/2) =9/10.5 = .8571 \n" ); document.write( ". \n" ); document.write( "the angle x = tan^-1 (.8571) = 40.60 degrees \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "check....9/10.5 = tan 40.6,,,,.8571,,,,,ok \n" ); document.write( " |