document.write( "Question 224253: Write the slope intercept form of the equation of the line described.\r
\n" ); document.write( "\n" ); document.write( "through:(4,2), parallel to \"-3x%2F4-5\"
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Algebra.Com's Answer #167550 by MathTherapy(10552)\"\" \"About 
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Write the slope intercept form of the equation of the line described.\r
\n" ); document.write( "\n" ); document.write( "through:(4,2), parallel to \"y+=+-3x%2F4+-+5\"\r
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\n" ); document.write( "\n" ); document.write( "Parallel linear equations have the same slope, and since the equation of line, \"y+=+%28-3%2F4%29x+-+5\" has a slope, or m of \"%28-+3%2F4%29\", then the slope for the new equation will also have a slope, or m of \"%28-3%2F4%29\".\r
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\n" ); document.write( "\n" ); document.write( "Using the point-slope formula, \"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\", and with \"y%5B1%5D+=+2_m+=+%28-3%2F4%29_and_x%5B1%5D+=+4\", we just need to substitute these values into the point-slope formula to find the equation of the described line.\r
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\n" ); document.write( "\n" ); document.write( "\"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+-+2+=+%28-3%2F4%29%2A%28x+-+4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+-+2+=+%28-3%2F4%29x+%2B+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28y+=+%28-3%2F4%29x+%2B+5%29\"
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