document.write( "Question 30008: tutors will you please help me with this problem I can't figure it out and this is my last one,
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document.write( " Two years ago,Kelli was three times as old as Tif was then. In 5 years Kelli will be only twice as old as Tif. How old is each now?In 5 years? and 2 years ago?
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document.write( " Kelli now-
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document.write( " Tif now-
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document.write( " Kelli in 5 years-
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document.write( " Tif in 5 years-
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document.write( " Kelli 2 years ago?
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document.write( " Tif 2 years ago? \n" );
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Algebra.Com's Answer #16755 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Kelli's age =x \n" ); document.write( "Tif's age = y \n" ); document.write( "Tif's age 2 years ago = y-2 \n" ); document.write( "Kelli's age 2 years ago = x-2 \n" ); document.write( "Five years from now: \n" ); document.write( "y+5 \n" ); document.write( "and \n" ); document.write( "x+5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equations: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Solve for y in first: \n" ); document.write( "y=3x-6+2 \n" ); document.write( "y=3x-4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sub for y in second. \n" ); document.write( "2x+10=3x-4+5 \n" ); document.write( "-x=-9 \n" ); document.write( "x=9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=3(9)-4 \n" ); document.write( "y=23\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, Tif is 9 years old and Kelli is 23 years old. \n" ); document.write( "Paul. \n" ); document.write( " \n" ); document.write( " |