document.write( "Question 223947: the second angle of a triangle is 3 times as large as the first. the third angle is 75 degrees more than the first. find the measure of the smallest angle.
\n" );
document.write( "A)105
\n" );
document.write( "B)15
\n" );
document.write( "C)21
\n" );
document.write( "D)75 \n" );
document.write( "
Algebra.Com's Answer #167482 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Let x = \"the first angle \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "\"the second angle of a triangle is 3 times as large as the first\" \n" ); document.write( "3x = the second angle \n" ); document.write( ": \n" ); document.write( "\"the third angle is 75 degrees more than the first.\" \n" ); document.write( "x + 75 = the third angle \n" ); document.write( ": \n" ); document.write( "find the measure of the smallest angle. \n" ); document.write( "we know the 3 angle add up to 180, therefore \n" ); document.write( ": \n" ); document.write( "x + 3x + (x+75) = 180 \n" ); document.write( ": \n" ); document.write( "x + 3x + x + 75 = 180 \n" ); document.write( ": \n" ); document.write( "subtract 75 from both sides, add up the x's \n" ); document.write( "5x = 180 - 75 \n" ); document.write( ": \n" ); document.write( "5x = 105 \n" ); document.write( ": \n" ); document.write( "divide both sides by 5 \n" ); document.write( "x = \n" ); document.write( "x = 21 \n" ); document.write( ": \n" ); document.write( "You should be able to find the other two angles, make sure all 3 add up to 180 \n" ); document.write( " |