document.write( "Question 224164: The wind is blowing at a steady rate of 10 mph. It takes a truck a total of 5 hours to travel 120 miles west against the wind and then 120 miles back with the wind. What is the trucks speed in still air? \n" ); document.write( "
Algebra.Com's Answer #167477 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The wind is blowing at a steady rate of 10 mph. It takes a truck a total of 5 hours to travel 120 miles west against the wind and then 120 miles back with the wind. What is the trucks speed in stil \n" ); document.write( ". \n" ); document.write( "Applying the distance formula: d = rt \n" ); document.write( ". \n" ); document.write( "Let x = speed of truck in still wind \n" ); document.write( "and y = time traveling against the wind \n" ); document.write( "then \n" ); document.write( "\"distance traveling against wind\" \n" ); document.write( "(x-10)y = 120 \n" ); document.write( "\"distance traveling with wind\" \n" ); document.write( "(x+10)(10-y) =120 \n" ); document.write( ". \n" ); document.write( "So, now we have two equations and two unknowns: \n" ); document.write( "(x-10)y = 120 \n" ); document.write( "(x+10)(10-y) =120 \n" ); document.write( ". \n" ); document.write( "Our system of equations: \n" ); document.write( "(x-10)y = 120 (equation 1) \n" ); document.write( ". \n" ); document.write( "(x+10)(10-y) =120 \n" ); document.write( "10x-xy-10y+100 = 120 (equation 2) \n" ); document.write( ". \n" ); document.write( "Solve equation 1 for y: \n" ); document.write( "y = 120/(x-10) \n" ); document.write( ". \n" ); document.write( "Plug the definition of y (above) into equation 2 and solve for x: \n" ); document.write( "10x-xy-10y+100 = 120 \n" ); document.write( "10x+100-xy-10y = 120 \n" ); document.write( "10x+100-(xy+10y) = 120 \n" ); document.write( "10x+100-y(x+10) = 120 \n" ); document.write( "10x+100-(120/(x-10))(x+10) = 120 \n" ); document.write( "Multiply BOTH sides by (x-10) to get rid of denominators: \n" ); document.write( "10x(x-10)+100(x-10)-120(x+10) = 120(x-10) \n" ); document.write( "10x^2-100x+100x-1000-120x-1200 = 120x-1200 \n" ); document.write( "10x^2-120x-2200 = 120x-1200 \n" ); document.write( "10x^2-240x-1000 = 0 \n" ); document.write( "x^2-24x-100 = 0 \n" ); document.write( "Since we can't factor, we must resort to the quadratic equation. Doing so will yield: \n" ); document.write( "x = {27.62, -3.62} \n" ); document.write( "A negative speed does NOT make sense, so toss it out leaving: \n" ); document.write( "x = 27.62 mph \n" ); document.write( ". \n" ); document.write( "Details of quadratic equation to follow: \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |