document.write( "Question 224169: three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer. \n" ); document.write( "
Algebra.Com's Answer #167475 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let x, x+2 & x+4 be the 3 odd integers. \n" ); document.write( "7(x+x+2)=9(x+4)+3 \n" ); document.write( "7(2x+2)=9x+36+3 \n" ); document.write( "14x+14=9x+39 \n" ); document.write( "14x-9x=39-14 \n" ); document.write( "5x=25 \n" ); document.write( "x=25/5 \n" ); document.write( "x=5 the smallest integer. \n" ); document.write( "5+2=7 the middle integer. \n" ); document.write( "5+4=9 the largest integer. \n" ); document.write( "Proof: \n" ); document.write( "7(5+7)=9*9+3 \n" ); document.write( "7*12=81+3 \n" ); document.write( "84=84 \n" ); document.write( " \n" ); document.write( " |