document.write( "Question 224169: three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer. \n" ); document.write( "
Algebra.Com's Answer #167475 by checkley77(12844)\"\" \"About 
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Let x, x+2 & x+4 be the 3 odd integers.
\n" ); document.write( "7(x+x+2)=9(x+4)+3
\n" ); document.write( "7(2x+2)=9x+36+3
\n" ); document.write( "14x+14=9x+39
\n" ); document.write( "14x-9x=39-14
\n" ); document.write( "5x=25
\n" ); document.write( "x=25/5
\n" ); document.write( "x=5 the smallest integer.
\n" ); document.write( "5+2=7 the middle integer.
\n" ); document.write( "5+4=9 the largest integer.
\n" ); document.write( "Proof:
\n" ); document.write( "7(5+7)=9*9+3
\n" ); document.write( "7*12=81+3
\n" ); document.write( "84=84
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