document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224100>Question 224100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1 . Which of the following sets is not closed under addition?\r<BR>\n" );
document.write( "\n" );
document.write( "A. odd numbers<BR>\n" );
document.write( "B. real numbers<BR>\n" );
document.write( "C. whole numbers<BR>\n" );
document.write( "D. negative integers<BR>\n" );
document.write( "= i got A\r<BR>\n" );
document.write( "\n" );
document.write( "2 . Which property is illustrated in the following?\r<BR>\n" );
document.write( "\n" );
document.write( "5 + 6 + 7 = 6 + 5 + 7\r<BR>\n" );
document.write( "\n" );
document.write( "A. commutative<BR>\n" );
document.write( "B. associative<BR>\n" );
document.write( "C. reflexive<BR>\n" );
document.write( "D. transitive<BR>\n" );
document.write( "= i got A\r<BR>\n" );
document.write( "\n" );
document.write( "3 . Which property is illustrated in the following?\r<BR>\n" );
document.write( "\n" );
document.write( "4 + (3 + x) = (4 + 3) + x\r<BR>\n" );
document.write( "\n" );
document.write( "A. commutative<BR>\n" );
document.write( "B. reflexive<BR>\n" );
document.write( "C. associative<BR>\n" );
document.write( "D. transitive<BR>\n" );
document.write( "= i got C\r<BR>\n" );
document.write( "\n" );
document.write( "4 . Is subtraction of real numbers commutative?\r<BR>\n" );
document.write( "\n" );
document.write( "A. Yes<BR>\n" );
document.write( "B. No<BR>\n" );
document.write( "= i got B\r<BR>\n" );
document.write( "\n" );
document.write( "5 . When using a number line to simplify 3 + (–6), you start at which point on the number line?\r<BR>\n" );
document.write( "\n" );
document.write( "A. origin<BR>\n" );
document.write( "B. –6<BR>\n" );
document.write( "C. 3<BR>\n" );
document.write( "D. –3<BR>\n" );
document.write( "= i got A\r<BR>\n" );
document.write( "\n" );
document.write( "6 . Simplify (–4 + 6) – 2.\r<BR>\n" );
document.write( "\n" );
document.write( "A. 8<BR>\n" );
document.write( "B. 4<BR>\n" );
document.write( "C. –4<BR>\n" );
document.write( "D. 0<BR>\n" );
document.write( "= i got D\r<BR>\n" );
document.write( "\n" );
document.write( "7 . Simplify –9 + (–3t) + (–21).\r<BR>\n" );
document.write( "\n" );
document.write( "A. –12 + (–3t)<BR>\n" );
document.write( "B. –33t <BR>\n" );
document.write( "C. –30 + (–3t)<BR>\n" );
document.write( "D. 12 + (–3t)<BR>\n" );
document.write( "= i got B\r<BR>\n" );
document.write( "\n" );
document.write( "8 . Simplify [–7 + 3] + (–4 + (–2)).\r<BR>\n" );
document.write( "\n" );
document.write( "A. –2<BR>\n" );
document.write( "B. –10<BR>\n" );
document.write( "C. –6<BR>\n" );
document.write( "D. 2 <BR>\n" );
document.write( "= i got B\r<BR>\n" );
document.write( "\n" );
document.write( "9 . Given x = –3, y = 6, and z = –4, evaluate –z + x – y.\r<BR>\n" );
document.write( "\n" );
document.write( "A. –7<BR>\n" );
document.write( "B. –13<BR>\n" );
document.write( "C. –5<BR>\n" );
document.write( "D. –1<BR>\n" );
document.write( "= i got C\r<BR>\n" );
document.write( "\n" );
document.write( "10 . Simplify x + 5 + [–(x) + (–14)].\r<BR>\n" );
document.write( "\n" );
document.write( "A. –9 + 2x<BR>\n" );
document.write( "B. 19<BR>\n" );
document.write( "C. –9 – x<BR>\n" );
document.write( "D. –9\r<BR>\n" );
document.write( "\n" );
document.write( "= i got A\r<BR>\n" );
document.write( "\n" );
document.write( "Is it all correct ?\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks ! :)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167431 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> # 1 Correct since odd + odd = even (eg: 3+5=8)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 2 Correct\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 3 Correct\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 4 Correct (eg: 5-3 does not equal 3-5)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 5 Incorrect. This question was pretty tricky since you can start at either 3 or -6, but I think the book is looking for you to start with the first given number 3 and then move to the left 6 units (ie subtract 6 from 3). So the answer is C)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 6 Correct\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 7 Incorrect. You can combine the terms -9 and -21 to get -30, but you CANNOT combine -30 and -3t to get -33t since they are NOT like terms. The only thing you can do is to leave them as they are and say that the answer is -30+(-3t) which means that the answer is C)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 8 Correct.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 9 Correct.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "# 10 Incorrect. Note how x + (-x) is the same as x - x which subtracts to 0x or just 0. This means that the 'x' terms just cancel out and go away. We're then left with 5 + (-14) = -9 which gives the answer D) -9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );