document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=224094>Question 224094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two small planes start from the same point and fly in opposite directions. The first plane is flying 25 mph slower than the second plane. In 2 hrs, the planes are 470 mi apart. Find the rate of each plane. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167425 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = rate of the slower plane (First plane!)<BR>\n" );
document.write( "x+25 = rate of the faster plane  (Second plane!)\r<BR>\n" );
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document.write( "The planes fly for 2 hours, where Distance = R*T\r<BR>\n" );
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document.write( "Distance between the planes = SUM of the distances.\r<BR>\n" );
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document.write( "R*T + R*T= 470 miles<BR>\n" );
document.write( "2*x + 2*(x+25)=470<BR>\n" );
document.write( "2x+2x + 50 = 470<BR>\n" );
document.write( "4x+50=470<BR>\n" );
document.write( "4x=420<BR>\n" );
document.write( "x=105 mph  First plane<BR>\n" );
document.write( "x+25= 105+25=130 mph  Second plane.\r<BR>\n" );
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document.write( "R^2\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje<BR>\n" );
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