document.write( "Question 224089: One car travels 20mph faster than another. While one of them travels 240 miles, the other travels 180 miles. Find the speed of both.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I do know that we are looking for the rate which is distance divided by time, but I am having problems setting it up.
\n" ); document.write( "

Algebra.Com's Answer #167420 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Time of one car is equal to time of the other car, where time is \"t=D%2Fr\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let x = speed of slower car (which travels the shorter distance!)
\n" ); document.write( "x+20 = speed of faster car (which travels the longer distance!)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D%2Fr=D%2Fr\"
\n" ); document.write( "\"240%2F%28x%2B20%29=180%2Fx\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Remember that \"a%2Fb=c%2Fd\" means \"ad=bc\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Likewise \"240%2F%28x%2B20%29=180%2Fx\" means \"240x=180%28x%2B20%29\"\r
\n" ); document.write( "\n" ); document.write( "\"240x=180x%2B3600\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 180x from each side:
\n" ); document.write( "\"60x=3600\"
\n" ); document.write( "\"x=60\" mph speed of slower car
\n" ); document.write( "\"x%2B20=80\" mph speed of faster car\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check: The faster car travels 240 miles at 80 mph = 3 hours
\n" ); document.write( "The slower car travels 180 miles at 60 mph = 3 hours.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );