document.write( "Question 29959: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water? \n" ); document.write( "
Algebra.Com's Answer #16740 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed of the boat in still water be x \n" ); document.write( "Against = - \n" ); document.write( "\"back again\" = + \n" ); document.write( "5hours and 20 minutes =5 1/3--->16/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation; \n" ); document.write( " \n" ); document.write( "Expand: \n" ); document.write( " \n" ); document.write( "Multiply the whole equation by 3 to remove the fraction: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the speed of the boat is 7.8mph in the still water. \n" ); document.write( "Paul. \n" ); document.write( " |