document.write( "Question 29959: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water? \n" ); document.write( "
Algebra.Com's Answer #16740 by Paul(988)\"\" \"About 
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Let the speed of the boat in still water be x
\n" ); document.write( "Against = -
\n" ); document.write( "\"back again\" = +
\n" ); document.write( "5hours and 20 minutes =5 1/3--->16/3\r
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\n" ); document.write( "\n" ); document.write( "Equation;
\n" ); document.write( " \"12%28x-3%29=%2816%28x%2B3%29%29%2F3\"
\n" ); document.write( "Expand:
\n" ); document.write( "\"12x-36=%2816x%2B48%29%2F3\"
\n" ); document.write( "Multiply the whole equation by 3 to remove the fraction:
\n" ); document.write( "\"3%28%2812x-36%29%2F1%29=3%28%2816x%2B48%29%2F3%29\"
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\n" ); document.write( "\n" ); document.write( "Hence, the speed of the boat is 7.8mph in the still water.
\n" ); document.write( "Paul.
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