document.write( "Question 224025: The bottom of a box is supposed to be a rectangle with the perimeter of 36 cm. The box must be 4 cm high. what dimensions give the maximum volume? \n" ); document.write( "
Algebra.Com's Answer #167395 by drj(1380)\"\" \"About 
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The bottom of a box is supposed to be a rectangle with the perimeter of 36 cm. The box must be 4 cm high. what dimensions give the maximum volume?\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The maximum volume is when the rectangle is a square and let s be the side of the square.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. The perimeter P of a rectangle (or square) means adding up all four sides. So P=s+s+s+s=4s since all four sides of the square are equal.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. But P=36=4s. Solving for s=36/4=9 cm.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Volume V=A*h of the box where A is the area of the square and h is the height given as h=4.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Area \"A=s%5E2\" for a square. So \"A=9%5E2=81\" square centimeters.\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Then V=A*h=81*4=324 cubic centimeters.\r
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\n" ); document.write( "\n" ); document.write( "Step 7. ANSWER: The maximum volume of the box is 324 cubic centimeters.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps and explanation were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for \r
\n" ); document.write( "\n" ); document.write( "Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. \r
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\n" ); document.write( "\n" ); document.write( "Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV\r
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