document.write( "Question 224053: What is the distance between the two points:
\n" ); document.write( "((( A 0,-6 B 14,0 ))).
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Algebra.Com's Answer #167379 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=0\" and \"y%5B1%5D=-6\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=14\" and \"y%5B2%5D=0\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%280-14%29%5E2%2B%28-6-0%29%5E2%29\" Plug in \"x%5B1%5D=0\", \"x%5B2%5D=14\", \"y%5B1%5D=-6\", and \"y%5B2%5D=0\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-14%29%5E2%2B%28-6-0%29%5E2%29\" Subtract \"14\" from \"0\" to get \"-14\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28-14%29%5E2%2B%28-6%29%5E2%29\" Subtract \"0\" from \"-6\" to get \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28196%2B%28-6%29%5E2%29\" Square \"-14\" to get \"196\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28196%2B36%29\" Square \"-6\" to get \"36\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28232%29\" Add \"196\" to \"36\" to get \"232\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=2%2Asqrt%2858%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=2%2Asqrt%2858%29\" \r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"d=15.232\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is approximately 15.232 units.
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