document.write( "Question 223987: I have been asked to solve (64/81) ^-1/2 = a/b where a= ? b= ?\r
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\n" ); document.write( "\n" ); document.write( "(1/1000) ^1/3= ?\r
\n" ); document.write( "\n" ); document.write( "I am not sure what they are asking me to do? Could someone please help me understand what is being asked of me? Thanks!
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Algebra.Com's Answer #167362 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
\"%2864%2F81%29%5E%28-1%2F2%29\"
\n" ); document.write( "By applying \"exponent rules\" we can make it positive by moving it to the denominator:
\n" ); document.write( "\"1%2F%2864%2F81%29%5E%281%2F2%29\"
\n" ); document.write( "And, of course, an exponent of 1/2 is actually a \"square root\":
\n" ); document.write( "\"1%2Fsqrt%2864%2F81%29\"
\n" ); document.write( "\"1%2F%288%2F9%29\"
\n" ); document.write( "\"9%2F8%29\"
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\n" ); document.write( "\"%281%2F1000%29%5E%281%2F3%29\"
\n" ); document.write( "Anything raised to the 1/3 power is actually a \"cube root\"
\n" ); document.write( "\"%281%2F1000%29%5E%281%2F3%29+=++1%2F10\"\r
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