document.write( "Question 223987: I have been asked to solve (64/81) ^-1/2 = a/b where a= ? b= ?\r
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document.write( "(1/1000) ^1/3= ?\r
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document.write( "I am not sure what they are asking me to do? Could someone please help me understand what is being asked of me? Thanks! \n" );
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Algebra.Com's Answer #167362 by nerdybill(7384) You can put this solution on YOUR website! \n" ); document.write( "By applying \"exponent rules\" we can make it positive by moving it to the denominator: \n" ); document.write( " \n" ); document.write( "And, of course, an exponent of 1/2 is actually a \"square root\": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "Anything raised to the 1/3 power is actually a \"cube root\" \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |