document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29812>Question 29812</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria present in a culture after t minutes is given as B = 10e^kt. If there are 7212 bacteria resent after 11 minutes, kind k. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16734 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B = 10e^(kt)\r<BR>\n" );
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document.write( "B = 7,212,   t = 11\r<BR>\n" );
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document.write( ".: 7212 = 10e^(11k)<BR>\n" );
document.write( "721.2 = e^(11k)\r<BR>\n" );
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document.write( "taking logs of both sides,\r<BR>\n" );
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document.write( "ln(721.2) = 11k<BR>\n" );
document.write( "11k = 6.5809<BR>\n" );
document.write( "k = 0.598265<BR>\n" );
document.write( "============ </SPAN>\n" );
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