document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=223775>Question 223775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with the following question:<BR>\n" );
document.write( "A Straight line has the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2y=12 ALIGN=MIDDLE  ALT=\"x-2y=12\"   DISABLED_style= \"max-width:90%; height:auto;\" > and it meets the axes at A and B. Find the distance of the mid-point of AB from the origin, Giving your answer in the form <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"k%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167323 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-2y=12<BR>\n" );
document.write( "-2y=12-x<BR>\n" );
document.write( "y=x/2 -6<BR>\n" );
document.write( "the y intercept where x=0 is y=-6<BR>\n" );
document.write( "x/2 -6=0<BR>\n" );
document.write( "x/2=6<BR>\n" );
document.write( "x=12<BR>\n" );
document.write( "The x intercept where y=0 is x=12<BR>\n" );
document.write( ".<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "6^2+12^2=c^2<BR>\n" );
document.write( "36+144=180<BR>\n" );
document.write( "sqrt(180)<BR>\n" );
document.write( "=sqrt(36*5)<BR>\n" );
document.write( "=6sqrt(5) length of AB<BR>\n" );
document.write( "3sqrt(5) midpoint of AB<BR>\n" );
document.write( ".<BR>\n" );
document.write( "tan=opp/adj=12/6=2 angle opposite line from midpoint to origin.<BR>\n" );
document.write( "tan^-1(2)=63.42... deg<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Law of cosines:<BR>\n" );
document.write( "a^2=b^2+c^2-2bc cos(a)<BR>\n" );
document.write( "a^2=6^2+(3sqrt(5))^2-2*6*3sqrt(5)*cos(63.42...)<BR>\n" );
document.write( "a^2=36+45-36sqrt(5)*cos A<BR>\n" );
document.write( "=45<BR>\n" );
document.write( "sqrt(45)<BR>\n" );
document.write( "=sqrt(9*5)<BR>\n" );
document.write( "=3sqrt(5)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );