document.write( "Question 29968: ok please help me,
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document.write( " aead is 5 years older than Jen. Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years. Find each person's age.\r
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document.write( " ed?
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document.write( " Jen? \n" );
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Algebra.Com's Answer #16727 by Fermat(136)![]() ![]() You can put this solution on YOUR website! Let E represent Ed's age \n" ); document.write( "Let J represent Jen's age\r \n" ); document.write( "\n" ); document.write( "The first part of the word problem says,\r \n" ); document.write( "\n" ); document.write( "Ed is 5 years older than Jen: this becomes,\r \n" ); document.write( "\n" ); document.write( "E = J + 5 \n" ); document.write( "==========\r \n" ); document.write( "\n" ); document.write( "The second part of the word problem says,\r \n" ); document.write( "\n" ); document.write( "Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years: and this becomes,\r \n" ); document.write( "\n" ); document.write( "4xJ + 3 = 3xE - 2 \n" ); document.write( "4J + 3 = 3E - 2 \n" ); document.write( "4J + 5 = 3E\r \n" ); document.write( "\n" ); document.write( "now we substitute for E = J + 5 into the above eqn.\r \n" ); document.write( "\n" ); document.write( "4J + 5 = 3(J + 5) \n" ); document.write( "4J + 5 = 3J + 15 \n" ); document.write( "J = 10 \n" ); document.write( "======\r \n" ); document.write( "\n" ); document.write( "E = J + 5 \n" ); document.write( "E = 15 \n" ); document.write( "====== \n" ); document.write( " |