document.write( "Question 223776: find the dimensions of the rectangle meeting the specified conditions
\n" ); document.write( "the perimeter is 320 cm and the width is 20 cm less than the length \n" ); document.write( "

Algebra.Com's Answer #167265 by drj(1380) $\"\"$ $\"About$

You can put this solution on YOUR website!
Find the dimensions of the rectangle meeting the specified conditions
\n" ); document.write( "the perimeter is 320 cm and the width is 20 cm less than the length\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let L be the length\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let L-20 be the width since it's 20 cm less than the length\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Perimeter P means adding up all 4 sides of the rectangle.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Then, P=L+L+L-20+L-20=320 since perimeter is 320 cm.\r
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Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

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This is an equation! Solutions: L=90.
Graphical form: Equation $\"L%2BL%2BL-20%2BL-20=320\"$ was fully solved.
Text form: L+L+L-20+L-20=320 simplifies to 0=0
Cartoon (animation) form: $\"simplify_cartoon%28+L%2BL%2BL-20%2BL-20=320+%29\"$
For tutors: simplify_cartoon( L+L+L-20+L-20=320 )
If you have a website, here's a link to this solution.

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DETAILED EXPLANATION

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Look at $\"L%2BL%2BL-highlight_red%28+20+%29%2BL-highlight_red%28+20+%29=320\"$ .
Added fractions or integers together
It becomes $\"L%2BL%2BL%2Bhighlight_green%28+-40+%29%2BL=320\"$ .
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Look at $\"L%2BL%2BL%2Bhighlight_red%28+-40+%29%2BL=320\"$ .
Moved $\"-40\"$ to the right of expression
It becomes $\"L%2BL%2BL%2BL%2Bhighlight_green%28+-40+%29=320\"$ .
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Look at $\"L%2BL%2BL%2BL%2Bhighlight_red%28+-40+%29=320\"$ .
Removed extra sign in front of $\"-40\"$
It becomes $\"L%2BL%2BL%2BL-highlight_green%28+40+%29=320\"$ .
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Look at

.
Eliminated similar terms $\"highlight_red%28+L+%29\"$ , $\"highlight_red%28+L+%29\"$ , $\"highlight_red%28+L+%29\"$ , $\"highlight_red%28+L+%29\"$ replacing them with $\"highlight_green%28+%281%2B1%2B1%2B1%29%2AL+%29\"$
It becomes $\"highlight_green%28+%281%2B1%2B1%2B1%29%2AL+%29-40=320\"$ .
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Look at

.
Added fractions or integers together
It becomes $\"%28highlight_green%28+4+%29%29%2AL-40=320\"$ .
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Look at $\"highlight_red%28+%28highlight_red%28+4+%29%29%2AL+%29-40=320\"$ .
Remove unneeded parentheses around factor $\"highlight_red%28+4+%29\"$
It becomes $\"highlight_green%28+4+%29%2AL-40=320\"$ .
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Look at $\"4%2AL-40=highlight_red%28+320+%29\"$ .
Moved these terms to the left $\"highlight_green%28+-320+%29\"$
It becomes $\"4%2AL-40-highlight_green%28+320+%29=0\"$ .
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Look at $\"4%2AL-highlight_red%28+40+%29-highlight_red%28+320+%29=0\"$ .
Added fractions or integers together
It becomes $\"4%2AL%2Bhighlight_green%28+-360+%29=0\"$ .
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Look at $\"4%2AL%2Bhighlight_red%28+-360+%29=0\"$ .
Removed extra sign in front of $\"-360\"$
It becomes $\"4%2AL-highlight_green%28+360+%29=0\"$ .
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Look at $\"highlight_red%28+4%2AL-360+%29=0\"$ .
Solved linear equation $\"highlight_red%28+4%2AL-360=0+%29\"$ equivalent to 4*L-360 =0
It becomes $\"highlight_green%28+0+%29=0\"$ .
Result: $\"0=0\"$
\n" ); document.write( "This is an equation! Solutions: L=90.

Universal Simplifier and Solver

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Done!

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\n" ); document.write( "\n" ); document.write( "With $\"L=90\"$ and L-20=70}}}. Also $\"P=2%2890%2B70%29=320\"$ which is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. The dimensions are that the length is 90 cm and the width is 70 cm.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "drjctu@gmail.com\r
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