document.write( "Question 223722: If the sum of three consecutive odd integers is 411, what is the first integer?\r
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\n" ); document.write( "\n" ); document.write( "A 131\r
\n" ); document.write( "\n" ); document.write( "B 133\r
\n" ); document.write( "\n" ); document.write( "C 135\r
\n" ); document.write( "\n" ); document.write( "D 137\r
\n" ); document.write( "\n" ); document.write( "E 139 \n" ); document.write( "

Algebra.Com's Answer #167224 by drj(1380) $\"\"$ $\"About$

You can put this solution on YOUR website!
If the sum of three consecutive odd integers is 411, what is the first integer?\r
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\n" ); document.write( "\n" ); document.write( "A 131\r
\n" ); document.write( "\n" ); document.write( "B 133\r
\n" ); document.write( "\n" ); document.write( "C 135\r
\n" ); document.write( "\n" ); document.write( "D 137\r
\n" ); document.write( "\n" ); document.write( "E 139\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let n be one odd integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let n+2 and n+4 be the next two odd consecutive integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Then n+(n+2)+(n+4)=411 be the sum of three odd integers\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Solving n+(n+2)+(n+4)=411 yields the following steps.\r
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Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

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\n" ); document.write( " YOUR ANSWER\n" ); document.write( "

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This is an equation! Solutions: n=135.
Graphical form: Equation $\"n%2B%28n%2B2%29%2B%28n%2B4%29=411\"$ was fully solved.
Text form: n+(n+2)+(n+4)=411 simplifies to 0=0
Cartoon (animation) form: $\"simplify_cartoon%28+n%2B%28n%2B2%29%2B%28n%2B4%29=411+%29\"$
For tutors: simplify_cartoon( n+(n+2)+(n+4)=411 )
If you have a website, here's a link to this solution.

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DETAILED EXPLANATION

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Look at $\"n%2Bhighlight_red%28+%28n%2B2%29+%29%2B%28n%2B4%29=411\"$ .
Remove unneeded parentheses around terms $\"highlight_red%28+n+%29\"$ , $\"highlight_red%28+2+%29\"$
It becomes $\"n%2Bhighlight_green%28+n+%29%2Bhighlight_green%28+2+%29%2B%28n%2B4%29=411\"$ .
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Look at $\"n%2Bn%2B2%2Bhighlight_red%28+%28n%2B4%29+%29=411\"$ .
Remove unneeded parentheses around terms $\"highlight_red%28+n+%29\"$ , $\"highlight_red%28+4+%29\"$
It becomes $\"n%2Bn%2B2%2Bhighlight_green%28+n+%29%2Bhighlight_green%28+4+%29=411\"$ .
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Look at $\"n%2Bn%2Bhighlight_red%28+2+%29%2Bn%2Bhighlight_red%28+4+%29=411\"$ .
Added fractions or integers together
It becomes $\"n%2Bn%2Bhighlight_green%28+6+%29%2Bn=411\"$ .
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Look at $\"n%2Bn%2Bhighlight_red%28+6+%29%2Bn=411\"$ .
Moved $\"6\"$ to the right of expression
It becomes $\"n%2Bn%2Bn%2Bhighlight_green%28+6+%29=411\"$ .
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Look at $\"highlight_red%28+n+%29%2Bhighlight_red%28+n+%29%2Bhighlight_red%28+n+%29%2B6=411\"$ .
Eliminated similar terms $\"highlight_red%28+n+%29\"$ , $\"highlight_red%28+n+%29\"$ , $\"highlight_red%28+n+%29\"$ replacing them with $\"highlight_green%28+%281%2B1%2B1%29%2An+%29\"$
It becomes $\"highlight_green%28+%281%2B1%2B1%29%2An+%29%2B6=411\"$ .
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Look at $\"%28highlight_red%28+1+%29%2Bhighlight_red%28+1+%29%2Bhighlight_red%28+1+%29%29%2An%2B6=411\"$ .
Added fractions or integers together
It becomes $\"%28highlight_green%28+3+%29%29%2An%2B6=411\"$ .
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Look at $\"highlight_red%28+%28highlight_red%28+3+%29%29%2An+%29%2B6=411\"$ .
Remove unneeded parentheses around factor $\"highlight_red%28+3+%29\"$
It becomes $\"highlight_green%28+3+%29%2An%2B6=411\"$ .
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Look at $\"3%2An%2B6=highlight_red%28+411+%29\"$ .
Moved these terms to the left $\"highlight_green%28+-411+%29\"$
It becomes $\"3%2An%2B6-highlight_green%28+411+%29=0\"$ .
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Look at $\"3%2An%2Bhighlight_red%28+6+%29-highlight_red%28+411+%29=0\"$ .
Added fractions or integers together
It becomes $\"3%2An%2Bhighlight_green%28+-405+%29=0\"$ .
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Look at $\"3%2An%2Bhighlight_red%28+-405+%29=0\"$ .
Removed extra sign in front of $\"-405\"$
It becomes $\"3%2An-highlight_green%28+405+%29=0\"$ .
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Look at $\"highlight_red%28+3%2An-405+%29=0\"$ .
Solved linear equation $\"highlight_red%28+3%2An-405=0+%29\"$ equivalent to 3*n-405 =0
It becomes $\"highlight_green%28+0+%29=0\"$ .
Result: $\"0=0\"$
\n" ); document.write( "This is an equation! Solutions: n=135.

Universal Simplifier and Solver

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Done!

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\n" ); document.write( "\n" ); document.write( " $\"n=135\"$ $\"n%2B2=137\"$ and $\"n%2B4=139\"$ \r
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\n" ); document.write( "\n" ); document.write( "Check sum...

135+137+139... which is a true statement\r
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\n" ); document.write( "\n" ); document.write( "Step 5. ANSWER: The three consecutive odd integers are 135, 137, and 139. The first integer is 135 so the solution is C. \r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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