document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=223381>Question 223381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice a number is 60 more than five times the number. what is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167196 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call \"a number\" x. Then twice a number would be 2x. And 5 times the number is 5x. Now we can translate \"twice a number is 60 more than five times the number\":<BR>\n" );
document.write( "2x = 60 + 5x<BR>\n" );
document.write( "Now we solve this for x. Subtract 5x from each side:<BR>\n" );
document.write( "-3x = 60<BR>\n" );
document.write( "Divide both sides by -3:<BR>\n" );
document.write( "x = -20<br><BR>\n" );
document.write( "Let's check. Twice -20 is -40. 5 times -20 is -100. And -40 <b>is</b> 60 more than -100.<BR>\n" );
document.write( "So the number is -20.<br><BR>\n" );
document.write( "Note: a solution provided by another is incorrect. It uses an incorrect equation and then checks/proves the incorrect answer with the incorrect equation. </SPAN>\n" );
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