document.write( "Question 223667: An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? \n" ); document.write( "
Algebra.Com's Answer #167191 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! a \"golden\" rectangle is one that when divided into a square and a rectangle (by a line across the width) \n" ); document.write( "___ the resulting smaller rectangle is similar to the original (also \"golden\") \n" ); document.write( "___ in other words, the ratio of the length to width is the same\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in mathematical terms ___ L/W = W/(L-W)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"cross\" multiplying __ L^2 - LW = W^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "36^2 - 36W = W^2 ___ 0 = W^2 + 36W - 1296\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use quadratic formula to find W \n" ); document.write( " |