document.write( "Question 223600: factor by grouping
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Algebra.Com's Answer #167180 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
\"7a%5E2-2bc-7ab%2B2ac\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Rearrange the order of terms so we can start grouping\r
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\n" ); document.write( "\n" ); document.write( "\"7a%5E2-2bc-7ab%2B2ac=7a%5E2-7ab%2B2ac-2ab=+%287a%5E2-7ab%29%2B%282ac-2bc%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Now factor out 7a from the first group and 2c from the second group.\r
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\n" ); document.write( "\n" ); document.write( "\"%287a%5E2-7ab%29%2B%282ac-2bc%29=+7a%28a-b%29%2B2c%28a-b%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. We see that (a-b) is a common factor in the two groups, so factor it out...\r
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\n" ); document.write( "\n" ); document.write( "\"7a%28a-b%29%2B2c%28a-b%29=%28a-b%29%287a%2B2c%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. ANSWER: \"7a%5E2-2bc-7ab%2B2ac=%28a-b%29%287a%2B2c%29\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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