document.write( "Question 223618: John has $2.05 in dimes and quarters. There are 3 more dimes than quarters. Find
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Algebra.Com's Answer #167174 by drj(1380)\"\" \"About 
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John has $2.05 in dimes and quarters. There are 3 more dimes than quarters. Find
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\n" ); document.write( "\n" ); document.write( "Step 1. Let x be the number of quarters.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let 0.25x be the dollar value of quarters.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let y be the number of dimes.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Let 0.10y be the dollar value of dimes.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Then 0.25x+0.10y=2.05 be the total dollar value.\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Also, y=x+3 since there are 3 more dimes than quarters\r
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\n" ); document.write( "\n" ); document.write( "Step 7. Our linear system of equation is given in Steps 4 and 5 shown below:\r
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\n" ); document.write( "\n" ); document.write( "\"0.25x%2B0.10y=2.05\"
\n" ); document.write( "\"-x%2By=3\"\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " We'll use substitution. After moving 0.1*y to the right, we get:
\n" ); document.write( " \"0.25%2Ax+=+2.05+-+0.1%2Ay\", or \"x+=+2.05%2F0.25+-+0.1%2Ay%2F0.25\". Substitute that
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\n" ); document.write( " \"-1%2A%282.05%2F0.25+-+0.1%2Ay%2F0.25%29+%2B+1%5Cy+=+3\" and simplify: So, we know that y=8. Since \"x+=+2.05%2F0.25+-+0.1%2Ay%2F0.25\", x=5.
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\n" ); document.write( " Answer: \"system%28+x=5%2C+y=8+%29\".
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\n" ); document.write( "\n" ); document.write( "So x=5 and y=8. The difference is 3 and the total dollar value is 0.25*5+0.10*8=2.05 which is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 8. ANSWER: The number of quarters is 5 and the number of dimes is 8.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit \r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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