document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=223555>Question 223555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A younger brother left his house on foot. Six minutes later his older brother followed him on a bicycle. If the younger brother is going 50 meters a minute and the older brother is going 200 meters a minute, how many minutes will it take for the older brother to catch up to the younger brother? Can you please explain how to solve this problem using a linear equation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #167173 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=167173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A younger brother left his house on foot.<BR>\n" );
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document.write( " Six minutes later his older brother followed him on a bicycle.<BR>\n" );
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document.write( " If the younger brother is going 50 meters a minute and the older brother is <BR>\n" );
document.write( "going 200 meters a minute, how many minutes will it take for the older brother<BR>\n" );
document.write( " to catch up to the younger brother?<BR>\n" );
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document.write( " Can you please explain how to solve this problem using a linear equation<BR>\n" );
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document.write( "Let t = time for older brother to catch up<BR>\n" );
document.write( "then <BR>\n" );
document.write( "(t+6) = time for the younger brother to be caught (he started 6 min sooner)<BR>\n" );
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document.write( "When this happens they both will have traveled the same distance<BR>\n" );
document.write( "write a distance equation: dist = speed * time<BR>\n" );
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document.write( "older's dist = younger's dist<BR>\n" );
document.write( "200t = 50(t+6)<BR>\n" );
document.write( "200t = 50t + 300<BR>\n" );
document.write( "200t - 50t = 300<BR>\n" );
document.write( "150t = 300<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=300%2F150 ALIGN=MIDDLE  ALT=\"300%2F150\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = 2 min<BR>\n" );
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document.write( "Check solution by finding the distance of each<BR>\n" );
document.write( "200*2 = 400 m<BR>\n" );
document.write( "50*(2+6) = 400 m </SPAN>\n" );
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