document.write( "Question 223646: The perimeter of a rectangle is 900 yards. What are the dimensions of the rectangle if the length is 30 yards more than the width? \n" ); document.write( "

Algebra.Com's Answer #167170 by drj(1380) $\"\"$ $\"About$

You can put this solution on YOUR website!
The perimeter of a rectangle is 900 yards. What are the dimensions of the rectangle if the length is 30 yards more than the width?\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Perimeter P means adding up all 4 sides of a rectangle.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let w be the width.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let w+30 be the length.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Then, P=w+w+w+30+w+30=4w+60=900\r
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Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

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\n" ); document.write( " YOUR ANSWER\n" ); document.write( "

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This is an equation! Solutions: w=210.
Graphical form: Equation $\"4w%2B60=900\"$ was fully solved.
Text form: 4w+60=900 simplifies to 0=0
Cartoon (animation) form: $\"simplify_cartoon%28+4w%2B60=900+%29\"$
For tutors: simplify_cartoon( 4w+60=900 )
If you have a website, here's a link to this solution.

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DETAILED EXPLANATION

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Look at $\"4%2Aw%2B60=highlight_red%28+900+%29\"$ .
Moved these terms to the left $\"highlight_green%28+-900+%29\"$
It becomes $\"4%2Aw%2B60-highlight_green%28+900+%29=0\"$ .
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Look at $\"4%2Aw%2Bhighlight_red%28+60+%29-highlight_red%28+900+%29=0\"$ .
Added fractions or integers together
It becomes $\"4%2Aw%2Bhighlight_green%28+-840+%29=0\"$ .
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Look at $\"4%2Aw%2Bhighlight_red%28+-840+%29=0\"$ .
Removed extra sign in front of $\"-840\"$
It becomes $\"4%2Aw-highlight_green%28+840+%29=0\"$ .
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Look at $\"highlight_red%28+4%2Aw-840+%29=0\"$ .
Solved linear equation $\"highlight_red%28+4%2Aw-840=0+%29\"$ equivalent to 4*w-840 =0
It becomes $\"highlight_green%28+0+%29=0\"$ .
Result: $\"0=0\"$
\n" ); document.write( "This is an equation! Solutions: w=210.

Universal Simplifier and Solver

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Done!

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\n" ); document.write( "\n" ); document.write( "With $\"w=210\"$ and $\"w%2B30=240\"$ . And $\"P=2%28210%2B240%29=900\"$ which is a true statement\r
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\n" ); document.write( "\n" ); document.write( "Step 5. ANSWER: The width is 210 yards and the length is 240 yards.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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